Determination of Fe²⁺ by KMnO₄ titration
eALOM Practical · AL Units 6 + 12 (transition metals, redox)
Aim
To determine the concentration of Fe²⁺ ions in a given solution by titration with standardised potassium permanganate.
Principle
Acidified KMnO₄ oxidises Fe²⁺ to Fe³⁺ while itself being reduced to Mn²⁺. The intense purple colour of MnO₄⁻ acts as its own indicator — the first persistent pink tinge marks the end-point.
Ionic equation:
MnO₄⁻ + 8H⁺ + 5Fe²⁺ → Mn²⁺ + 5Fe³⁺ + 4H₂O
Stoichiometry: 1 mol MnO₄⁻ reacts with 5 mol Fe²⁺.
MnO₄⁻ + 8H⁺ + 5Fe²⁺ → Mn²⁺ + 5Fe³⁺ + 4H₂O
Stoichiometry: 1 mol MnO₄⁻ reacts with 5 mol Fe²⁺.
Apparatus
Procedure
- Rinse the burette with a small portion of KMnO₄ solution; discard the rinse. Fill the burette and record the initial reading (read the upper meniscus — solution is opaque purple).
- Pipette 25.00 cm³ of the Fe²⁺ solution into a clean conical flask.
- Add about 25 cm³ of dilute H₂SO₄ (this provides the H⁺ needed by the half-equation).
- Place the flask on a white tile under the burette. Titrate, swirling continuously. The pink colour disappears rapidly at first.
- End-point is reached when one drop produces a persistent pale pink colour that does not fade within ~30 s.
- Repeat for concordant titres (agreeing within 0.10 cm³).
Observation table
| Rough | 1 | 2 | 3 | |
|---|---|---|---|---|
| Final burette reading / cm³ | ||||
| Initial burette reading / cm³ | ||||
| Volume KMnO₄ used / cm³ |
Calculation helper
Common errors examiners flag
- Reading the lower meniscus by mistake — KMnO₄ is opaque, use the upper.
- Using HCl instead of H₂SO₄ — chloride is oxidised by MnO₄⁻, giving false high titres.
- Adding the KMnO₄ too fast at the start — local concentration spikes give MnO₂ (brown), invalidating the titration.
- Forgetting to swirl — gives premature pink colour, false low titre.
Past-paper questions on this practical
(Will be topic-tagged in Phase 2.) Most years between 2015 and 2024 include at least one structured Paper II question involving KMnO₄ titration of Fe²⁺ or related redox.